A) \[\frac{5}{108}\]
B) \[\frac{1}{6}\]
C) \[\frac{5}{18}\]
D) \[\frac{4}{9}\]
Correct Answer: D
Solution :
\[\therefore \]Required probability \[=\frac{{{\,}^{4}}{{C}_{2}}+{{\,}^{5}}{{C}_{2}}}{{{\,}^{9}}{{C}_{2}}}\] \[=\frac{6+10}{36}=\frac{16}{36}\] \[=\frac{4}{9}\]You need to login to perform this action.
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