A) - 2 and 15
B) - 3 and - 10
C) - 4 and- 9
D) -5 and -6
Correct Answer: B
Solution :
The quadratic equation with the roots - 2 and -15 is \[{{x}^{2}}-(-2-15)x+(-2)(-15)=0\] \[\Rightarrow \] \[{{x}^{2}}+17x+30=0\] Then, according to question, new quadratic equation is \[{{x}^{2}}+13x+30=0\] \[\Rightarrow \] \[(x+3)(x+10)=0\] \[\Rightarrow \] \[x=-3,-10\] which are the actual required roots.You need to login to perform this action.
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