A) \[\frac{16}{3}{{a}^{2}}\text{sq units}\]
B) \[\frac{8}{3}\text{sq}\,\text{units}\]
C) \[\frac{\text{4}}{\text{3}}{{\text{a}}^{\text{2}}}\text{sq}\,\text{units}\]
D) None of these
Correct Answer: A
Solution :
The focus of the parabolas \[{{y}^{2}}=4a(x+a)\]and\[{{y}^{2}}=-4a(x-a)\] are \[(-a,0)\] and \[(a,0)\] respectively. The required area is shown in the figure which is given by as following.You need to login to perform this action.
You will be redirected in
3 sec