A) {\[x:x\] is a real number and \[{{x}^{2}}-1=0\]}
B) {\[x:x\] is a real number and\[~{{x}^{2}}+1=0\]}
C) {\[x:x\] is real number and\[{{x}^{2}}-9=0\]}
D) {\[x:x\] is a real number and\[{{x}^{2}}=x+2\]}
Correct Answer: B
Solution :
First, we define all the four given sets (a) {\[x:x\] is a real number and\[{{x}^{2}}-1=0\]}\[=\{1,-1\}\] (b) {\[x:x\] is a real number and \[{{x}^{2}}+1=0\}\]\[=\phi \] (c) {\[x:x\] is a real number and\[{{x}^{2}}-9=0\]}\[=\{3,-3\}\] (d) {\[x:x\] is a real number and\[{{x}^{2}}=x+2\]} \[=\{-1,2\}\] Clearly, (b) is empty set.You need to login to perform this action.
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