A) 300 kg-wt
B) 400 kg-wt
C) 500 kg-wt
D) 600 kg-wt
Correct Answer: D
Solution :
Here, \[F-{{f}_{k}}=ma\] \[F={{f}_{k}}+ma\] \[F=\mu mg+ma\] \[F=m(\mu g+a)\] \[\therefore \] \[F=(500+1500)(0.2\times 10+1)\] \[F=6000\,N\] \[f=6000\,kg-wt\]You need to login to perform this action.
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