A) \[\frac{1}{10\pi }\]
B) \[\frac{1}{20\pi }\]
C) \[\frac{1}{40\pi }\]
D) \[\frac{1}{60\pi }\]
Correct Answer: B
Solution :
\[\tan \phi \text{=}\frac{{{X}_{L}}}{R}\] \[\therefore \] \[\tan {{45}^{o}}=\frac{L\omega }{R}\] \[L=\frac{R}{\omega }=\frac{100}{2\pi \times 1000}\] \[(\because \,tan{{45}^{o}}=1)\] \[L=\frac{1}{20\pi }\]You need to login to perform this action.
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