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BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    The equilibrium constant for a reaction, \[{{N}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2NO(g)\] is \[4\times {{10}^{-4}}\] at \[\text{2000}\,\text{K}\text{.}\] In the presence of catalyst, the equilibrium is attained 10 times faster. The equilibrium constant in presence of catalyst at 2000 K is

    A) \[10\times {{10}^{-4}}\]               

    B)  \[4\times {{10}^{-2}}\] 

    C)         \[4\times {{10}^{-4}}\] 

    D)         \[4\times {{10}^{-4}}\]

    Correct Answer: C

    Solution :

    The value of equilibrium constant is not affected by catalyst. A catalyst only changes the time required to achieve equilibrium. \[\therefore \] The equilibrium constant will remain same, ie,\[4\times {{10}^{-4}}.\]


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