A) \[1.76\,\times {{10}^{-4}}C/kg\]
B) \[1.76\,\times {{10}^{14}}C/kg\]
C) \[1.76\,\times {{10}^{11}}C/kg\]
D) \[1.76\,\times {{10}^{-16}}C/kg\]
Correct Answer: C
Solution :
\[\frac{1}{2}m{{v}^{2}}=eV\]or \[\frac{e}{m}=\frac{{{v}^{2}}}{2V}=\frac{{{(8.4\times {{10}^{6}})}^{2}}}{2\times 200}\] \[=1.76\times {{10}^{11}}\,C/kg\]You need to login to perform this action.
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