A) H
B) \[{{\text{H}}^{\text{+}}}\]
C) \[{{\text{H}}^{-}}\]
D) \[2{{H}_{2}}\]
Correct Answer: C
Solution :
\[\text{LiAl}{{\text{H}}_{\text{4}}}\]is actually \[\text{Li }\!\![\!\!\text{ Al(}{{\text{H}}_{\text{4}}}\text{) }\!\!]\!\!\text{ }\text{.}\]In it, the ligand present is hydride ion, i.e., \[{{\text{H}}^{-}}.\]You need to login to perform this action.
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