A) \[4x-y+1=0\]
B) \[33x+12y+7=0\]
C) \[12x+33y=7\]
D) None of these
Correct Answer: C
Solution :
Here, \[x+y+\lambda (2x-y+1)=0\] Since, each line passes through the point of intersection of the lines. \[x+y=0\]and \[2x-y+1=0,\] which is \[(-1/3,1/3).\] \[\therefore \] Slope of the required line, \[m=\frac{-1}{\frac{4-1/3}{1+1/3}}=\frac{-4}{11}\] \[\therefore \]The required line is \[y-\frac{1}{3}=-\frac{4}{11}\left( x+\frac{1}{3} \right)\] \[\Rightarrow \] \[12x+33y=7\]You need to login to perform this action.
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