A) \[y=2\]
B) \[y=2x\]
C) \[y=2x-4\]
D) \[y=2{{x}^{2}}-4\]
Correct Answer: C
Solution :
Let \[y=2x-4\,\,\,\Rightarrow \,\,\,\,\frac{dy}{dx}=2\] \[\therefore \] \[{{\left( \frac{dy}{dx} \right)}^{2}}-x\left( \frac{dy}{dx} \right)+y={{(2)}^{3}}-x(2)+y=0\] \[\therefore \] \[y=2x-4\]is a solution.You need to login to perform this action.
You will be redirected in
3 sec