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BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    For the transistor circuit shown in figure, if \[\beta =100,\]voltage drop across emitter and base is 0.7 V, then the value of \[{{\text{V}}_{\text{CE}}}\]will be

    A)  Zero                                     

    B)  5 V

    C)  10 V                     

    D)         13 V

    Correct Answer: D

    Solution :

    We have, \[{{i}_{b}}=\frac{5-0.7}{8.6}=0.5\,mA\] \[\therefore \]  \[{{i}_{c}}={{\beta }_{ib}}=100\times 0.5\,mA\]                 \[=50\,mA\] By using \[{{V}_{CE}}={{V}_{CC}}-{{i}_{C}}{{R}_{L}}\] \[=18-50\times {{10}^{-3}}\times 100\]                 \[=18-5=13\,V\]


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