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BCECE Engineering BCECE Engineering Solved Paper-2012

  • question_answer
    The domain of the real function\[f(x)=\frac{1}{\sqrt{4-{{x}^{2}}}}\]is

    A)  the set of all real numbers

    B)         the set of all positive real numbers

    C)         \[(-2,2)\]

    D)         \[[-2,2]\]

    Correct Answer: C

    Solution :

    Given, \[F(x)=\frac{1}{\sqrt{4-{{x}^{2}}}}\] For domain of \[f(x),\]                 \[4-{{x}^{2}}>0\] \[\Rightarrow \]\[{{x}^{2}}<4\] \[\Rightarrow \]\[-2<x<2\] \[\therefore \]Domain \[=(-2,2)\]


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