A) 9.25
B) 4.75
C) 3.75
D) 8.25
Correct Answer: B
Solution :
Solution of \[\text{N}{{\text{H}}_{\text{4}}}\text{OH}\] and \[\text{N}{{\text{H}}_{\text{4}}}\text{Cl}\]acts as a basic buffer solution. For basic buffer solution, \[pOH=p{{K}_{b}}+\log \frac{[Salt]}{[Base]}\] \[pOH=14-pH=14-9.25=4.75\] \[4.75=p{{K}_{b}}+\log \frac{0.1}{0.1}\] \[p{{K}_{b}}=4.75\]You need to login to perform this action.
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