A) \[\frac{4\sqrt{3}}{2}m\]
B) \[\frac{\sqrt{3}+3}{2}m\]
C) \[\frac{3-\sqrt{3}}{2}m\]
D) \[\frac{\sqrt{3}}{2}m\]
Correct Answer: C
Solution :
Let \[h\] be the height of the tower. In \[\Delta \Alpha \Beta C,\] \[\tan {{60}^{o}}=\frac{h}{\left( \frac{1}{\sqrt{3}+1} \right)}\] \[\Rightarrow \] \[\frac{\sqrt{3}}{\sqrt{3}+1}=\frac{h}{1}\] \[\Rightarrow \] \[h=\frac{\sqrt{3}(\sqrt{3}-1)}{3-1}\] \[\Rightarrow \] \[=\frac{3-\sqrt{3}}{2}\]You need to login to perform this action.
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