A) \[(2,2)\]
B) \[(4,-4)\]
C) \[(4,4)\]
D) \[(-2,2)\]
Correct Answer: C
Solution :
Given, equations of parabola are \[{{x}^{2}}=4y\]and \[{{y}^{2}}=4x\] ?(i) \[\therefore \] \[{{\left( \frac{{{x}^{2}}}{4} \right)}^{2}}=4x\Rightarrow {{x}^{4}}-64x=0\] \[\Rightarrow \] \[x=0,x=4\] On putting the value of x in Eq. (i), we get \[y=0\]and \[y=4,-4\] (\[\because \,\,y=-4\]does not satisfy the equation\[{{x}^{2}}=4y\]) Hence, points of intersection are (0, 0) and (4, 4).You need to login to perform this action.
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