A) \[\frac{{{(ab)}^{n}}}{n!}\]
B) \[{{e}^{b}}.\frac{{{a}^{n}}}{n!}\]
C) \[{{e}^{a}}.\frac{{{b}^{n}}}{n!}\]
D) \[{{e}^{a+b}}\frac{{{(ab)}^{n}}}{n!}\]
Correct Answer: C
Solution :
\[1+\frac{(a+bx)}{11}+\frac{{{(a+bx)}^{2}}}{2!}\] \[+\frac{{{(a+bx)}^{3}}}{3!}+...\infty ={{e}^{a+bx}}\] \[\therefore \]Coefficient of \[{{x}^{n}}\] \[{{e}^{a}}{{e}^{bx}}={{e}^{a}}.\frac{{{(b)}^{n}}}{n!}\]You need to login to perform this action.
You will be redirected in
3 sec