A) b - a
B) -b
C) b - 2a
D) None of these
Correct Answer: C
Solution :
In \[\Delta \Alpha \Beta C,AB+BC=AC\] \[\Rightarrow \] \[AC=a+b\] AD is parallel to BC and AD = 2BC \[\therefore \] \[AD=2b\] In \[\Delta ACD,AC+CD=AD\] \[\Rightarrow \] \[CD=2b-(a+b)=b-a\] Now, \[CE=CD+DE=b-2a\]You need to login to perform this action.
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