A) \[(a+b)\]
B) \[(a-b)\]
C) 2 a
D) 2b
Correct Answer: B
Solution :
\[\text{OABCDE}\]is a regular hexagon. Let \[\overline{\text{OA}}=\bar{a}\]and \[AB=b,\]join OB OC, we have \[OB=OA+AB=a+b\] Since, OC is parallel to AB and double of AB. \[\therefore \] \[OC=2\,AB=2b\] Now, \[BC=OC-OB\] \[=2b-(a+b)=b-a\] \[CD=-OA=-a\] and \[DE=-AB=-b\] Also, \[EO=BC=-(b-a)=a-b\]You need to login to perform this action.
You will be redirected in
3 sec