A) \[1+2{{x}^{2}}\]
B) \[~2+{{x}^{2}}\]
C) \[1+x\]
D) \[~2+x\]
Correct Answer: B
Solution :
Given, \[g(x)=1+\sqrt{x}\] and \[f\{g(x)\}=3+2\sqrt{x}+x\] ?.(i) \[\Rightarrow \] \[f(1+\sqrt{x})=3+2\sqrt{x}+x\] Put \[1+\sqrt{x}=y\]\[\Rightarrow \]\[x={{(y-1)}^{2}}\] \[\therefore \] \[f(y)=3+2(y-1)+{{(y-1)}^{2}}=2+{{y}^{2}}\] \[\therefore \] \[f(x)=2+{{x}^{2}}\]You need to login to perform this action.
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