A) \[{{3.2}^{o}}\]
B) \[{{1.6}^{o}}\]
C) \[{{0.8}^{o}}\]
D) \[{{5.0}^{o}}\]
Correct Answer: A
Solution :
\[\frac{KCl}{{{M}_{1}}{{V}_{1}}}=\frac{AsN{{O}_{3}}}{{{M}_{2}}{{V}_{2}}}\] \[{{M}_{1}}=\frac{1\times 20}{25}\] \[=0.8\,M\] \[i=(1+x)\] \[=1+1=2\] \[\therefore \] \[\Delta {{T}_{f}}=molality\times {{K}_{f}}\times i\] \[=0.8\times 2\times 2\] \[={{3.2}^{o}}\]You need to login to perform this action.
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