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BCECE Engineering BCECE Engineering Solved Paper-2013

  • question_answer
    The magnetic flux through a circuit of resistance R changes by an amount \[\Delta \phi \] in a time \[\Delta t.\]Then the total quantity of electric charge Q that passes any point in the circuit during the time \[\Delta t\]is represented by

    A)  \[Q=\frac{\Delta \phi }{\Delta t}\]          

    B)         \[Q=\frac{\Delta \phi }{R}\]       

    C)         \[Q=R.\frac{\Delta \phi }{\Delta t}\]      

    D)         \[Q=\frac{1}{R}\frac{\Delta \phi }{\Delta t}\]

    Correct Answer: B

    Solution :

    We have \[e=\left| \frac{\Delta \phi }{\Delta t} \right|\] \[\therefore \]  Current, \[l=\frac{e}{R}=\frac{\Delta \phi }{R\Delta \phi }\] So, charge \[Q=l.\Delta t=\frac{\Delta \phi }{R\Delta \phi }.\Delta t=\frac{\Delta \phi }{R}\]


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