A) \[10\text{ }m/{{s}^{2}}\]
B) \[20\text{ }m/{{s}^{2}}\]
C) \[~40\text{ }m/{{s}^{2}}\]
D) None of these
Correct Answer: D
Solution :
By the relation, \[g=\frac{GM}{{{R}^{2}}}\]we have \[\frac{{{g}_{P}}}{{{g}_{e}}}=\frac{{{M}_{p}}}{{{M}_{e}}}\times \frac{R_{e}^{2}}{R_{p}^{2}}=2\times {{(2)}^{2}}\] \[\therefore \] \[{{g}_{p}}=8\times 10=80\,m/{{s}^{2}}\]
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