A) \[v=C\frac{\sin i}{\cos r}\]
B) \[v=C\frac{\cos r}{\cos \,i}\]
C) \[v=C\frac{\sin r}{\sin \,i}\]
D) \[v=C\frac{\sin i}{\sin \,r}\]
Correct Answer: C
Solution :
We have, \[\mu =\frac{\sin i}{\sin r}\]and also \[\mu =\frac{c}{v}\] \[\therefore \] \[\frac{c}{v}=\frac{\sin i}{\sin r}\] \[\Rightarrow \] \[v=c.\left( \frac{\sin r}{\sin i} \right)\]You need to login to perform this action.
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