A) 2 rad/s
B) 4 rad/s
C) 16 rad/s
D) \[\sqrt{21}\,rad/s\]
Correct Answer: B
Solution :
Maximum tension \[=\frac{m{{v}^{2}}}{r}+mg\] \[3.7\times 10=\frac{0.5{{v}^{2}}}{4}+0.5\times 10\] \[\Rightarrow \] \[v=16\,m/s\] \[\therefore \] \[\omega =\frac{v}{r}=\frac{16}{4}=4\,rad/s\]You need to login to perform this action.
You will be redirected in
3 sec