Compartments A and B have the following combinations solution | Column 1 | Column II |
| I. \[\text{0}\text{.1M KCl}\] II. \[\text{0}\text{.1 }\!\!%\!\!\text{ (m/V)NaCl}\] III. \[\text{18g}{{\text{L}}^{-1}}\] glucose IV. \[\text{20 }\!\!%\!\!\text{ (m/V)}\] | \[\text{0}\text{.2 M KCl}\] \[\text{10 }\!\!%\!\!\text{ (m/V)NaCl}\] \[34.2g{{L}^{-1}}\]sucrose \[\text{10 }\!\!%\!\!\text{ (m/V)}\]glucose |
A) I only
B) III only
C) IV only
D) II only
Correct Answer: B
Solution :
Isotonic solution have same molarty. Molarity of 18 g glucose \[=\frac{18}{180}/\frac{1000}{1000}=0.1\] Molarity of 34.2 g sucrose \[=\frac{34.2}{34.2}/\frac{1000}{1000}=0.1\] The concentration of \[18g{{L}^{-1}}\] glucose is same to \[34.2g{{L}^{-1}}\] sucrose.
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