BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    If \[\text{A=3\hat{i}+4\hat{j}}\] and \[\text{B =7\hat{i}+24\hat{j},}\], then the vector having the same magnitude as Band parallel to  A is 

    A) \[\text{15\hat{i}+20\hat{j}}\]                    

    B) \[\text{5\hat{i}-3\hat{j}}\]

    C) \[\text{15\hat{i}+13\hat{j}}\]                    

    D) \[\text{5\hat{i}+14\hat{j}}\]

    Correct Answer: A

    Solution :

    Unit vector in the direction of A will be \[A=\frac{3\hat{i}+4\hat{j}}{\sqrt{{{3}^{2}}+{{4}^{2}}}}=\frac{3\hat{i}+4\hat{j}}{5}\]                 \[|B|=\sqrt{{{7}^{2}}+{{(24)}^{2}}}\]                 \[=\sqrt{625}=25\] Required vector\[=25\left( \frac{3\hat{i}+4\hat{j}}{5} \right)=15\hat{i}+20\hat{j}\]


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