A) (ii) and (iii)
B) (i), (ii) and (iv)
C) (i), (ii) and (iii)
D) (i) and (iv)
Correct Answer: A
Solution :
Peroxide ion is \[O_{2}^{2-}\]. \[O_{2}^{2-}(18)=\sigma 1{{s}^{2}},\] \[_{\sigma }^{*}1{{s}^{2}},\] \[\sigma 2{{s}^{2}},\] \[_{\sigma }^{*}2{{s}^{2}},\] \[\sigma 2p_{z}^{2},\] \[\pi 2p_{x}^{2}\approx \pi 2p_{y}^{2},_{\pi }^{*}2p_{x}^{2}\approx _{\pi }^{*}2p_{y}^{2}\] Bonds order \[=\frac{{{N}_{b}}-{{N}_{a}}}{2}=\frac{10-8}{2}=1\] It contains four completely filled antibonding molecular orbitals. Since, all the electrons are paired, \[O_{2}^{2-}\]is diamagnetic. Peroxide ion is isoelectronic with argon, not with neon.You need to login to perform this action.
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