A) \[\text{I,II, IV, III}\]
B) \[\text{IV,I, II, III}\]
C) \[\text{III,IV, I, II}\]
D) \[\text{III,II, IV, I}\]
Correct Answer: D
Solution :
Magnetic moment \[(\mu )\] is given as\[\mu =\sqrt{n(n+2)}\]where, n is number of unpaired electrons. \[F{{e}^{2+}}:[Ar]3{{d}^{6}};\]number of unpaired electrons = 4 \[T{{i}^{2+}}:[Ar]3{{d}^{2}};\]number of unpaired electrons =2 \[C{{u}^{2+}}:[Ar]3{{d}^{9}};\]number of unpaired electrons = 1 \[{{V}^{2+}}:[Ar]3{{d}^{3}};\]number of unpaired electrons = 3 Hence, the increasing order of magnetic moment is as \[C{{u}^{2+}}<T{{i}^{2+}}<{{V}^{2+}}<F{{e}^{2+}}\]You need to login to perform this action.
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