A) 3 : 2 : 5
B) 5 : 2 : 3
C) 5 : 3 : 2
D) 2 : 3 : 5
Correct Answer: A
Solution :
Lowering of vapour pressure is a colligative property. It depends on the number of particles of the solute. \[BaC{{l}_{2}}\rightleftharpoons B{{a}^{2+}}+2C{{l}^{-}};\text{3 ions}\] \[NaCl\rightleftharpoons N{{a}^{+}}+C{{l}^{-}};\text{2 ions}\] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\rightleftharpoons 2A{{l}^{3}}+3SO_{4}^{3-};\text{5 ions}\] Hence, the ratio of lowering of vapour pressure is 3: 2: 5.You need to login to perform this action.
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