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BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    The activation energy for a reaction at the temperature T K was found to be 2. 303 RT J \[\text{mo}{{\text{l}}^{\text{-1}}}\]. The ratio of the rate constant to Arrhenius factor is

    A) \[\text{1}{{0}^{\text{-1}}}\]                                       

    B) \[\text{1}{{0}^{\text{-2}}}\]

    C) \[\text{2}\times \text{1}{{0}^{\text{-3}}}\]                         

    D) \[\text{2}\times \text{1}{{0}^{\text{-2}}}\]

    Correct Answer: A

    Solution :

    Arrhenius equation is, rate constant , \[k=A{{e}^{-{{E}_{a}}/RT}}\]                                 \[k=A{{e}^{-2.303RT/RT}}\Rightarrow \frac{k}{A}={{e}^{-2.303}}\] On solving , we get \[\frac{k}{A}={{10}^{-1}}\]


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