A) 25
B) 24
C) 23
D) None of the above
Correct Answer: D
Solution :
Given, \[\left| \begin{matrix} {{x}^{2}}+x & 3x-1 & -x+3 \\ 2x+1 & 2+{{x}^{2}} & {{x}^{3}}-3 \\ x-3 & {{x}^{2}}+4 & 3x \\ \end{matrix} \right|\] \[={{a}_{0}}+{{a}_{1}}x+......+{{a}_{7}}{{x}^{7}}\] On putting \[x=0,\]we get \[\left| \begin{matrix} 0 & -1 & 3 \\ 1 & 2 & -3 \\ -3 & 4 & 0 \\ \end{matrix} \right|={{a}_{0}}\] \[\Rightarrow \] \[0+1(0-9)+3(4+6)={{a}_{0}}\] \[\Rightarrow \] \[30-9={{a}_{0}}\] \[\Rightarrow \] \[{{a}_{0}}=21\]You need to login to perform this action.
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