A) \[\frac{{{E}_{0}}}{R}\]
B) \[\frac{E_{0}^{2}}{4R}\]
C) \[\frac{4R}{{{E}_{0}}}\]
D) \[\frac{R}{{{E}_{0}}}\]
Correct Answer: B
Solution :
For L-R combination, Given, \[{{X}_{l}}=R\] Impedance \[Z=\sqrt{{{R}^{2}}+{{R}^{2}}}\] \[=\sqrt{2}R\] Power consumed \[={{\left( \frac{{{V}_{rms}}}{Z} \right)}^{2}}R\] \[={{\left( \frac{{{E}_{0}}/\sqrt{2}}{\sqrt{2}R} \right)}^{2}}R=\frac{E_{0}^{2}}{4R}\]You need to login to perform this action.
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