A) \[\text{5}{}^\circ \text{C}/\text{cm}\]
B) \[\text{15}{}^\circ \text{C}/\text{cm}\]
C) \[\text{25}{}^\circ \text{C}/\text{cm}\]
D) \[\text{5}0{}^\circ \text{C}/\text{cm}\]
Correct Answer: C
Solution :
\[\frac{\Delta Q}{\Delta t}=KA\frac{\Delta \theta }{\Delta x}\] Thermal gradient \[=\frac{\left( \frac{\Delta Q}{\Delta t} \right)}{KA}=\frac{10}{0.4}={{25}^{o}}C/cm\]You need to login to perform this action.
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