A) \[\sqrt{\frac{{{E}_{K}}}{2}}\]
B) \[\frac{1}{\sqrt{2{{E}_{K}}}}\]
C) \[\frac{2}{\sqrt{{{E}_{K}}}}\]
D) \[\frac{\sqrt{3{{E}_{K}}}}{2}\]
Correct Answer: C
Solution :
\[{{\lambda }_{\text{photon}}}=\frac{hc}{{{E}_{k}}}\] \[{{\lambda }_{\text{electron}}}=\frac{h}{\sqrt{2m{{E}_{k}}}}\] \[\frac{{{\text{ }\!\!\lambda\!\!\text{ }}_{\text{photon}}}}{{{\text{ }\!\!\lambda\!\!\text{ }}_{\text{electron}}}}\text{=}\frac{\text{1}}{\sqrt{{{\text{E}}_{\text{k}}}}}\]You need to login to perform this action.
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