A) 4: 3
B) 3:4
C) 1 :2
D) 2 :1
Correct Answer: C
Solution :
Rate of disintegration \[\alpha \] number of atoms left For \[X\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{4}\] For \[Y\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{1}}=\frac{1}{2}\] \[\therefore \] \[\frac{{{R}_{X}}}{{{R}_{\gamma }}}=\frac{\frac{{{N}_{0}}}{4}}{\frac{{{N}_{0}}}{2}}=\frac{1}{2}\]You need to login to perform this action.
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