A) 0.1 mA
B) 0.2mA
C) 4.9mA
D) 9.2mA
Correct Answer: C
Solution :
\[\alpha =\frac{\Delta {{i}_{c}}}{\Delta {{i}_{e}}}\] Given, \[\alpha =0.98,\Delta {{i}_{e}}=5mA\] \[\Delta {{i}_{c}}=(\alpha )(\Delta {{i}_{e}})=(0.98)(5mA)\] \[=4.9mA\]You need to login to perform this action.
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