A) \[~\text{dH}=\text{ TdS }-\text{ Vdp}\]
B) \[~\text{dH}=\text{SdT}+\text{ Vdp}\]
C) \[\text{dH}=-\text{SdT}-\text{Vdp}\]
D) \[\text{dH }=\text{ dE }-\text{ pdV}\]
Correct Answer: A
Solution :
Given, \[dE=TdS-pdV\] ? (i) \[H=E+pV\] ? (ii) Differentiating Eq. (ii) \[dH=dE+pdV+Vdp\] ? (iii) From Eq.(i) and (iii),we get \[dH=Tds-Vdp\]You need to login to perform this action.
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