A) 2.52
B) 2.20
C) 2.35
D) 2.01
Correct Answer: B
Solution :
As the size of atom (element) increases, energy required to overcome the attractive force on outermost electron decreases. Li. Na. K and Rb are the members of same group and have the following order of size \[\text{Li}<\text{Na}<\text{K}<\text{Rb}\] Thus, the energy in case of K is intermediate of Rb and Na,/.e., \[\text{2}.\text{3}0<\text{K}>\text{2}.0\text{9}\] or the energy for K is 2.20 \[\text{eV}\].You need to login to perform this action.
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