A) nucleophilic attack, transfer of \[{{\text{H}}^{\text{-}}}\] and transfer of \[{{\text{H}}^{+}}\]
B) transfer of \[{{\text{H}}^{-}}\], transfer of \[{{\text{H}}^{+}}\] and nucleophilic attack
C) transfer of \[{{\text{H}}^{+}}\] , nucleophilic attack and transfer of \[{{\text{H}}^{-}}\]
D) electrophilic attack by \[\text{O}{{\text{H}}^{-}}\], transfer of \[{{\text{H}}^{-}}\] and
Correct Answer: A
Solution :
The Cannizzaro reaction is as \[\text{HCHO + HCHO}\xrightarrow{\text{KOH(con}\text{.)}}\underset{\text{methyl alcohol}}{\mathop{\text{C}{{\text{H}}_{\text{3}}}\text{OH}}}\,\text{+}\underset{\text{acetic acid}}{\mathop{\text{HCOO}{{\text{k}}^{\text{+}}}}}\,\]The mechanism of Cannizzaro reaction is as Step I Attack of nucleophile \[\text{O}{{\text{H}}^{-}}\]to the carbonyl carbonYou need to login to perform this action.
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