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BCECE Engineering BCECE Engineering Solved Paper-2014

  • question_answer
    In Kjeldahl's method, ammonia from 5 got food neutralizes \[\text{3}0\text{ c}{{\text{m}}^{\text{3}}}\] of 0.1 N acid. The percentage of nitrogen in the food is

    A)  0.84                      

    B) 8.4      

    C) 16.8                       

    D) 1.68

    Correct Answer: A

    Solution :

    From Kjeldahl's method, percentage of nitrogen \[=\frac{1.0\times N\times V}{w}=\frac{1.4\times 0.1\times 30}{5}\] \[=0.84%\]


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