A) \[x=10.25\sin (\omega t+\phi )\]
B) \[x=10.25\sin (\omega t-\phi )\]
C) \[x=11.25\sin (\omega t+\phi )\]
D) \[x=11.25\sin (\omega t-\phi )\]
Correct Answer: C
Solution :
The resultant equation is \[x=A\sin (\omega t+\phi )\] \[\sum{{{A}_{x}}}=2+4\cos {{30}^{\circ }}+6\cos {{60}^{\circ }}=8.46\]You need to login to perform this action.
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