A) 7.2g
B) 2.3g
C) 1.8g
D) 4.1 g
Correct Answer: C
Solution :
1 mole of NO gives = 1 mol \[N{{O}_{2}}\] Hence, mol gives \[\text{1}\text{.20 g NO=}\frac{\text{1}\text{.20}}{\text{30}}\text{mol}\] gives \[\text{=1 }\!\!\times\!\!\text{ }\frac{\text{1}\text{.20}}{\text{30}}\text{mol N}{{\text{O}}_{\text{2}}}\text{=}\frac{\text{1}\text{.20}}{\text{30}}\text{ }\!\!\times\!\!\text{ 46 g N}{{\text{O}}_{\text{2}}}\text{=1}\text{.84 g N}{{\text{O}}_{\text{2}}}\]You need to login to perform this action.
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