A) \[F{{e}^{3+}}\]decreases
B) \[F{{e}^{3+}}\]increases
C) \[F{{e}^{2+}}\]decreases
D) \[F{{e}^{2+}},F{{e}^{3+}}\]remain unchanged
Correct Answer: A
Solution :
Cell reaction, \[2F{{e}^{3+}}+Fe\to 3F{{e}^{2+}}\] \[E_{Cell}^{\circ }=0.77-(-0.44)=1.21\text{V}\] \[\Rightarrow \]\[F{{e}^{3+}}\]and Fe will reduce.You need to login to perform this action.
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