A) 3
B) 4
C) 2
D) 1
Correct Answer: B
Solution :
The electronic configuration of \[{{M}^{x+}}(Z=25)\]is \[1{{s}^{2}},2{{s}^{2}},2{{p}^{6}},3{{s}^{2}},3{{p}^{6}},3{{d}^{5}},4{{s}^{2}}\] Magnetic moment \[=\sqrt{n(n+2)}BM\] \[=\sqrt{5(5+2)}BM=\sqrt{35}BM\] Given, magnetic moment \[=\sqrt{15}BM=\sqrt{3(3+2)}BM\] Hence, unpaired electrons =3 \[\therefore \]The oxidation number \[x\] is 4.You need to login to perform this action.
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