A) I and II
B) I, II and III
C) II and IV
D) II, III and IV
Correct Answer: C
Solution :
There are two factors that determine the reactivity of the halogenation of alkanes. (i) Lesser the positive value .of \[{{E}_{act}}\] of the first chain propagating step, more reactive is the halogen. (ii) Higher the negative value of overall heat of reaction \[(\Delta \Eta _{r}^{\circ })\] , more reactive is the halogen. This explains high reactivity and explosive violence with which \[{{F}_{2}}\] reacts with \[\text{C}{{\text{H}}_{\text{4}}}\] .You need to login to perform this action.
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