A) \[16.23%\]
B) \[13.21%\]
C) \[11.50%\]
D) \[15.81%\]
Correct Answer: C
Solution :
Theoretical value of dipole moment of a 100% ionic character = e x d \[=(1.60\times {{10}^{-19}}C)(1.41\times {{10}^{-10}}m)\] \[=2.26\times {{10}^{-29}}Cm\] Observed value of dipole moment \[=2.60\times {{10}^{-30}}Cm\] \[\therefore \] Per cent ionic character \[\text{=}\frac{\text{Obersved value}}{\text{Theortical value}}\text{ }\!\!\times\!\!\text{ 100}\] \[=\frac{2.60\times {{10}^{-30}}}{2.26\times {{10}^{-29}}}\times 100=11.5%\]You need to login to perform this action.
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