A) 0.4
B) 0.8
C) 1.2
D) 1.4
Correct Answer: C
Solution :
We have, \[P(A\cup B)=0.6,P(A\cap B)=0.2\] \[\therefore \] \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] \[\Rightarrow \] \[0.6=P(A)+P(B)-0.2\] \[\Rightarrow \] \[P(A)+P(B)=0.8\] \[\Rightarrow \] \[1-P(\bar{A})+1-P(\bar{B})=0.8\] \[\Rightarrow \] \[P(\bar{A})+P(\bar{B})=1.2\]You need to login to perform this action.
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