A) 0.9
B) 0
C) 1.8
D) -0.9
Correct Answer: B
Solution :
\[\int_{0}^{0.9}{[x-2[x]]dx}\] \[=\int_{0}^{0.9}{[x-2\times 0]dx}\] \[=\int_{0}^{0.9}{[x]dx}=\int_{0}^{0.9}{\text{0 dx = 0}}\]You need to login to perform this action.
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