A) 4
B) 3
C) \[\sqrt{12}\]
D) 7/2
Correct Answer: A
Solution :
Let e be the eccentricity of the ellipse \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{9}=1\] Then, \[e=\sqrt{1-\frac{9}{16}}=\frac{\sqrt{7}}{4}\] So, coordinates of the foci of the ellipse are \[(\pm \sqrt{7,0})\]. The radius of the circle having centre at (0,3) and passing through foci \[=\sqrt{{{(0-\sqrt{7})}^{2}}+{{(3-0)}^{2}}}=4\]You need to login to perform this action.
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